Please enable Javascript for better experience...
Read and Write a JSON file in C#
By Rahul Kumar Jha | Aug 5, 2020 | In Articles | Total Views [ 19649 ]
(0 Like)
Rate

In this article we will explain how to read and write a json file in C# using Newtonsoft.Json.

Introduction

This is very simple article having simple steps to read and write a json file in C#. To continue with this, first of all please install Newtonsoft.Json package. For demo purpose I have created a simple MVC application having a model, partial view, controller and a json file. We will list few youtube urls in json file, convert it into model using Newtonsoft.Json package and render it to partial view.

Model VideoFeeder

Add a class and name it VideoFeederModel. Copy below code.

public class VideoFeederModel
{
public string URL { get; set; }
public string Title { get; set; }
}

ViewFeeder.Json

Add a json file and add below data.

[
{
"URL": "https://www.youtube.com/embed/NuWuNAb_4AM",
"Title": "E-Bill validitiy extension"
},
{
"URL": "https://www.youtube.com/embed/h8x0p0_aeiE",
"Title": "FAQ ON EMI RELIEF FAQ ON EMI MORATORIUM FAQ RBI MORATORIUM"
},
{
"URL": "https://www.youtube.com/embed/Ad8rUXaPmIc",
"Title": "RBI Moratorium Notification EMI Moratorium EMI Relief during lock down"
},
{
"URL": "https://www.youtube.com/embed/DuMxQUPTHvI",
"Title": "Corporate Affairs Relief due to COVID 19 Corona Analysis by CA Sri Niwash Jha"
},
{
"URL": "https://www.youtube.com/embed/wS27m-em_wQ",
"Title": "Relief to financial services, custom, and department of fisheries due to COVID19"
}
]

HomeController

Add HomeController and add below method

public ActionResult VideoFeeder()
{
string filePath = Server.MapPath("~/JSON/VideoFeeder.json");
List<VideoFeederModel> model = JsonConvert.DeserializeObject<List<VideoFeederModel>>(System.IO.File.ReadAllText(filePath));

return PartialView("_VideoFeederPartial", model);
}

_VideoFeederPartial.Cshtml

Now add a partial view and name it as "_VideoFeederPartial" and add below code.

@model List<VideoFeederModel>
<div class="row">
<div class="container content">
<h2>VIDEOS</h2>
@{ foreach (var item in Model)
{
<div class="video-container">
<p class="video-thumb">
<iframe class="video"
src="@item.URL" frameborder="1"
allow="accelerometer; encrypted-media; gyroscope; picture-in-picture" allowfullscreen="">
</iframe>
</p>
<h4>@item.Title</h4>
</div>
}}
</div>
</div>

Now call the action ViewFeeder() in index.cshtml file and run the application. You will see video link added to your page. Hope this helps you.

Share this

About the Author

Rahul Kumar Jha
Rahul Kumar Jha
Founder, Developer dotnet-concept.com

Public profile: user/profile/99900001


Has working experience in different phases of Software Development Life Cycle (SDLC) in CMS, Gaming, Health Care and Financial Services domain using Agile pattern. Working experience in Design patterns, ASP.NET, MVC, ANGULAR, ANGULAR JS, Windows application, WCF, ADO.NET, SQL Server and Test Driven Development (TDD) environment with JQuery, JavaScript, N-Unit, Entity Frameworks, LINQ, Code Refactoring and Business Objects Models.

User's Comments


 
Please SignUp/Login to comment...

Or comment as anonymous...
* Name
* Email ID
Comment
 
 
 
 
 
 
Sponsors